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The perpenidicular drawn from the centre...

The perpenidicular drawn from the centre of a circle bisects any chord of the circle. The following are the steps involved in proving the above result. Arrange them in sequential order.
ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PS_MATH_VIII_C16_E05_015_Q01.png" width="80%"gt
(A) Let `bar(OD) _|_ bar(AB)` .
(B) Let AB be the chord of the circle with centre O.
(C ) `Delta ODA -= Delta ODB` ( By RHS congruence property).
(D ) `OA =OB ` (radii), `OD= OD` ( common side) and `/_ ODA =/_ ODB =90^(@)`
(E ) `AD=DB` ( corresponding parts in congurents triangles ).

A

BADCE

B

BCDAE

C

DBACDE

D

BDEAC

Text Solution

Verified by Experts

The correct Answer is:
a

`(B),(A),(D) ,(C )` and `(E)` is the required sequential order.
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