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In the above figure, bar(AB)||bar(DE) an...


In the above figure, `bar(AB)||bar(DE)` and ACE is a straight line . I f `/_ABC =30^(@)` and `/_CDE =20^(@)`, then find `/_BCD`.

A

`40^(@)`

B

`50^(@)`

C

`60^(@)`

D

`70^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B

Draw `PQ ||bar(AB)` through point C.
`/_ABC =/_BCQ =30^(@)" "[ :' ` Alterante angle ]
`/_ CD E= /_DCQ =20^(@)" "[ :' `Alternate angle ]
`implies /_ BCD =30^(@)+20^(@)=50^(@)`
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