If the intercepts made by tangent, normal to a rectangular `x^2-y^2 =a^2` with x-axis are `a_1,a_2` and with y-axis are `b_1, b_2` then `a_1,a_2 + b_1b_2=`

If the intercepts made by tangent,normal to a rectangular x^(2)-y^(2)=a^(2) with x -axis are a_(1),a_(2) and with y-axis are b_(1),b_(2) then a_(1),a_(2)+b_(1)b_(2)=

If the tangent and normal to xy=c^2 at a given point on it cut off intercepts a_1, a_2 on one axis and b_1, b_2 on the other axis, then a_1 a_2 + b_1 b_2 = (A) -1 (B) 1 (C) 0 (D) a_1 a_2 b_1 b_2

Let a_1" and "b_1 be intercepts made by the tangent at point P on xy=c^2 on x-axis and y-axis and a_2" and "b_2 be intercepts made by the normal at P on x-axis and y-axis. Then

If the tangent and the normal to x^2-y^2=4 at a point cut off intercepts a_1,a_2 on the x-axis respectively & b_1,b_2 on the y-axis respectively. Then the value of a_1a_2+b_1b_2 is equal to:

The area under the curve y=sinx , y=cosx , y-axis is A_1 , y=sinx , y=cosx , x-axis is A_2 then A_1:A_2 is

If b,c B are given, and if b lt c , show that (a_1 -a_2)^2 +(a_1 + a_2)^2 tan^2 B= 4b^2 , where a_1,a_2 are the two values of the third side.

Let L be the line created by rotating the tangent line to the parabola y=x^2 at the point (1,1), about A by an angle (-pi/4). Let B be the other intersection of line L with y=x^2. If the area inclosed by the L and the parabola is (a_1/a_2) where a_1 and a_2 are co prime numbers, find(a_1+a_2)