" (25.) "" If "y=[log_(cos x)sin x}" (logain "x" cos "x)^(-1)+sin^(-1)((2x)/(1+x^(2)))

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If y={log_(cos x)sin x}{log_(sin x)cos x)^(-1)+sin^(-1)((2x)/(1+x^(2))) find (dy)/(dx) at x=(pi)/(4)

If y={(log)cos x sin x}{(log)_(sin x)cos x}^(-1)+sin^(-1)((2x)/(1+x^(2))) fin d (dy)/(dx)atx=(pi)/(4)

y={log_(cos x)sin x}{log_(sin x)cos x}^(-1)+sin^(-1)(2(x)/(1+x^(2))) then find (dy)/(dx)=?

log_(cos x)sin x+log_(sin x)cos x=2then x=

If: (log_(cos x) sin x) + (log_(sin x)cos x)=2 , then, in general, x=

(1+sin x+cos x)^(2)=2(1+sin x)(1+cos x)

(cos x)/(1-sin x)=(1+cos x+sin x)/(1+cos x-sin x)

If y = Tan ^(-1) ((cos x- sin x)/(cos x + sin x)) then (d ^(2) y)/(dx ^(2))=

lim_(x=0)(log_(sin x)cos x)/(log_(sin((x)/(2)))cos((x)/(2)))

{ cos (sin ^(-1) x)}^(2) ={sin (cos ^(-1) x)}^(2)