The value of `a` for the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1,(a > b),` if the extremities of the latus rectum of the ellipse having positive ordinates lie on the parabola `x^2=2(y-2)` is ___

Ellipse (x^2)/(a^2)+(y^2)/(b^2)=1,(a > b), If the extremities of the latus rectum of the with positive ordinates lie on the parabola x^(2) = 3(y + 3) , then length of the transverse axis of ellipse is

For the ellipse (x^(2))/(4) + (y^(2))/(3) = 1 , the ends of the two latus rectum are the four points

Find the extremities of latus rectum of the parabola y=x^(2)-2x+3

Find the length of the latus rectum of the ellipse x^2/36+y^2/25=1

The lenth of the latus rectum of the ellipse 3x^2+y^2=12 is :

Consider an ellipse x^(2)/a^(2)+y^(2)/b^(2)=1 What is the length of the latus rectum of the ellipse 25x^(2)+16y^(2)=400 ?

Find the equation of the normal to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at the positive end of the latus rectum.