If `A={1,2,4}` then `n{P(A)}` is

Let P(n) denote the statement: 2^(n)ge n! .Show that P(1),P(2),P(3) are true butP(4) is not true.

If 4^n/(n+1) lt ((2n)!)/((n!)^2) , then P(n) is true for

if .^(2n+1)P_(n-1):^(2n-1)P_(n)=7:10 , then .^(n)P_(3) equals

If P(n,4)=12P(n,2) then value of n is

Two consecutive number p,p + 1 are removed from natural numbers. 1,2,3, 4……….., n-1, n such that arithmetic mean of these number reduces by 1, then (n-p) is equal to.

If P (n) = 2 + 4 + 6+…+ 2n, n in N then P(k) = k (k +1) + 2 implies P (k +1 ) = (k +1 ) (k + 2)+ 2 AA k in N. So, we can conciude that P (n) = n (n +1) + 2 for

If P(n) stands for the statement n(n+1)(n+2) is divisible by 3, then what is P(4).

If P(n) is the statement: n(n + 1) is even, then what is P(4) ?