Two capacitors with capacitances `C_(1) and C_(2)` are connected in parallel. Find the resultant capacitance.

Assertion: If three capacitors of capacitance C_(1) lt C_(2) lt C_(3) are connected in parallel then their equivalent capacitance C_(p) gt C_(s) Reason: (1)/(C_(p)) = (1)/(C_(1)) + (1)/(C_(2)) + (1)/(C_(3))

Two capacitors of capacitances C_(1) and C_(2) are connected in parallel. If a charge q is given to the assembly, the charge gets shared. The ratio of the charge on the capacitor C_(1) to the charge on C_(2) is

Two capacitors of capacitances C_(1)=2muF and C_(2)=8muF are connected in series and the resulting combination is connected across a 300V battery. Calculate the charge, potential difference and energy stored in the capacitor separately.

Two capacitors of capacitance C_(1) and C_(2) are connected in parallel and a charge Q is delivered to the combination. The two are then disconnected and reconnected in series. What are the new potential differences and charge on the capacitors?

Theee capacitors of capacitance 1,2,and 3 muF connected in series. Find the resultant capacitance.

Two capacitors of capacitance C_(1) = 2 muF and C_(2) = 8 mu F are connected in series and the resulting combination is connected across 300 volts. Calculate the charge, potential difference and energy stored in the capacitor separately.

The equivalent capacitance of three capacitors of capacitance C_(1):C_(2) and C_(3) are connected in parallel is 12 units and product C_(1).C_(2).C_(3) = 48 . When the capacitors C_(1) and C_(2) are connected in parallel, the equivalent capacitance is 6 units. then the capacitance are

Two capacitor C_1 with capacitance 2C and C_2 with capacitance C are connected in parallel. They are changed and then the batter is removed. If a material of dielectric constant K is inserted in C_2 . Find final potential across them.