When air in between the plates of a capacitor is replaced by mica of dielectric constant 6, its capacity

If the distance between the plates of parallel plate capacitor is halved and the dielectric constant of dielectric is doubled, then its capacity will

Assertion : If the distance between parallel plates of a capacitor is halved and dielectric constant is made three times, then the capacitance becomes 6 times. Reason : Capacity of the capacitor depends upon the nature of the material between the plates.

Assertion: If the distance between parallel plates of a capacitor is halved and dielectric constant is made three times, then the capacitor becomes 6 times. Reason: Capacity of the capacitor does not depend upon the nature of the meterial.

If the gap between the plates of a parallel plate capacitor is filled with medium of dielectric constant k=2 , then the field between them

A parallel plate capacitor with air between the plates has a capacitance C. If the distance between the plates is doubled and the space between the plates is filled with a dielectric of dielectric constant 6, then the capacitance will become.

A capacitor of capacitance C is charged to potential difference V and then disconnected from the battery. The air dielectric of capacitor is replaced by another dielectric of dielectric constant K. The fractional decrease in energy of the capacitor is

The capacity of a capacitor becomes 10 mu F when air between the plates is replaced by a dielectric slab of K = 2. What is the capacity of the condenser with air in between the plates ?

Statement I: When air between the plates of a parallel plate condenser is replaced by an insulating dielectric medium, its capacity decreases. Statement II: Electric field intensity between the plates with dielectric in between is reduced.

The capacity of condenser containing air is 4muF . What will be its capacity if the air is replaced by a material of dielectric constant 5 ?

Half of the space between parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plates . if initially the capacity is C, then the new capacity will be :