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When 12.0g of C reacted with a limited q...

When `12.0g` of `C` reacted with a limited quantity of oxygen, `57.5 kcal `of heat was produced. Calculate the number of `CO` and number of moles of `CO_(2)` produced.
Given `C +O_(2) rarr CO_(2), Delta_(f)H = - 94.05 kcal`
`C +1//2O_(2) rarr CO, Delta_(f)H =- 26.41 kcal `

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When 12.0 g of carbon reacted with limited quantity of oxygen, 57.5 kcal of heat was produced, calculate the number of moles of CO produced (Delta_(f)H(CO_(2))=-94.5 cal, Delta_(f)H(CO)= -21.41kcal.

C + O_(2) rarr CO_(2), CO + (1)/(2) O_(2) rarr CO_(2), Then Delta_(f) H for CO will be

C_(("graphite")) + O_(2(g)) to CO_(2(g)) - 94.0 kcal

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