If `(sqrt(3))b x+a y=2a b` touches the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1` , then the eccentric angle of the point of contact is `pi/6` (b) `pi/4` (c) `pi/3` (d) `pi/2`

If (x)/(a)+(y)/(b)=sqrt(2) touches the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1, then find the eccentric angle theta of point of contact.

The distance of a point on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 from the center is 2. Then the eccentric angle of the point is (pi)/(4) (b) (3 pi)/(4) (c) (5 pi)/(6) (d) (pi)/(6)

The line (x)/(a)cos theta-(y)/(b)sin theta=1 will touch the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at point P whose eccentric angle is (A) theta(B)pi-theta(C)pi+theta(D)2 pi-theta

If the eccentricity of the hyperbola x^(2)-y^(2)(sec)alpha=5 is sqrt(3) xx the eccentricity of the ellipse x^(2)(sec)^(2)alpha+y^(2)=25, then a value of alpha is : (a) (pi)/(6) (b) (pi)/(4) (c) (pi)/(3) (d) (pi)/(2)

sin^(-1)((-1)/2) (a) pi/3 (b) -pi/3 (c) pi/6 (d) -pi/6

The eccentric angle of a point on the ellipse x^2/6 + y^2/2 = 1 whose distance from the centre of the ellipse is 2, is (A) pi/4 (B) 7pi/6 (C) 3pi/2 (D) 5pi/3

For f(x)=sin^2x ,x in (0,pi) point of inflection is: pi/6 (b) (2pi)/4 (c) (3pi)/4 (d) (4pi)/3

The angle between the planes 2x-y+z=6 and x+y+2z=7 is (A) pi/4 (B) pi/6 (C) pi/3 (D) pi/2

The locus of the point of intersection of tangents to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 at the points whose eccentric angles differ by pi//2 , is