An `alpha-` particle of mass `6.65 times 10^(-27)kg` is travelling at right angles to a magnetic field with a speed of `6 times 10^(5)ms^(-1)`. The strength of the magnetic field is 0.2 T. Calculate the force on the `alpha-` particle and its acceleration.

An alpha -particle of mass 6.65xx10^-27kg is travelling at right angles to a magnetic field with a speed of 6xx10^5ms^-1 . The strength of the magnetic field is 0.2T . Calculate the force on the alpha -particle and its acceleration.

An alpha -particle of mass 6.65xx10^-27kg is travelling at right angles to a magnetic field with a speed of 6xx10^5ms^-1 . The strength of the magnetic field is 0.2T . Calculate the force on the alpha -particle and its acceleration.

An alpha particle is located at a point where electric field strength is 3xx10^(4)N//C . Calculate (a) the force on the alpha - particle (b) its acceleration.

An alpha- particle of mass 6.65xx10^(-27) kg travels perpendicular to a magnetic of 0.2 T with a speed of 6xx10^(5)ms^(-1) . Calculate the acceleration of the alpha- particle. Given the charge on the electron is 1.6xx10^(-19)C .

A proton (mass = 1.6times10^(-27)Kg enters into a magnetic field of induction 3T with a velocity of 10^(7)ms^(-1) at 30 to the field.The force on the proton?

An alpha - particle enters a magnetic field of 1 T with a velocity 10^(6) m/s in a direction perpendicular to the field . The force on alpha - particle is ________ .

An alpha particle travels at an angle of 30^(@) to a magnetic field 0.8 T with a velocity of 10^(5) m/s. The magnitude of force will be-

A particle of mass 6.65 x 10^(-27) kg having positive charge equal to two times of electron, moves with a speed of 6x109 m/s in a direction perpendicular to that of a given magnetic field of flux density 0.4 we ber/m2 Find the acceleration of the particle.