The equation of the transvers axis of the hyperbola `(x-3)^2+(y+1)^2=(4x+3y)^2` is `x+3y=0` (b) `4x+3y=9` `3x-4y=13` (d) `4x+3y=0`

Axis of the parabola x ^(2) -4x-3y+10=0 is

The midpoint of the chord 4x-3y=5 of the hyperbola 2x^(2)-3y^(2)=12 is

The equation of conjugate axis of the hyperbola xy-3y-4x+7=0 is y+x=3 (b) y+x=7y-x=3 (d) none of these

The combined equation of asymptotes to the hyperbola x^2 + 4xy + 3y^2 +4x-3y +1=0 are

The equation of the asymptotes of a hyperbola are 4x - 3y + 8 = 0 and 3x + 4y - 7 = 0 , then

Find the equation of the tangent line to the curve y=(3x^2-1)/x at the point (1,2) is (a) 4x-y-1=0 (b) 4x+y+2=0 (c)x-y-1=0 (d) 4x-y-2=0

The equation of the asymptotes of a hyperbola are 4x+3y+2=0 and 3x-4y+1=0 then equations of axes arex