The equation of a circle which has a tangent `3x+4y=6` and two normals given by `(x-1)(y-2)=0` is

The equation of the circle which has a tangent 2x-y-1=0 at (3, 5) on it and with the centre on x+y=5 , is

The equation of the circle which has a tangent 2x-y-1=0 at (3, 5) on it and with the centre on x+y=5 , is

The equation of the circle which has a radius 5 and tangent as the line 3x-4y+5=0 at (1,2) is

The equation of the circle which has normals (x-1).(y-2)=0 and a tangent 3x+4y=6 is (a) x^2+y^2-2x-4y+4=0 (b) x^2+y^2-2x-4y+5=0 (c) x^2+y^2=5 (d) (x-3)^2+(y-4)^2=5

The equation of the circle which has normals x-1)*(y-2)=0 and a tangent 3x+4y=6 is x^(2)+y^(2)-2x-4y+4=0x^(2)+y^(2)-2x-4y+5=0x^(2)+y^(2)=5(x-3)^(2)+(y-4)^(2)=5

The equation of the circle which has normals (x-1).(y-2)=0 and a tangent 3x+4y=6 is (a) x^2+y^2-2x-4y+4=0 (b) x^2+y^2-2x-4y+5=0 (c) x^2+y^2=5 (d) (x-3)^2+(y-4)^2=5

The equation of the circle which has normals x-1).(y-2)=0 and a tangent 3x+4y=6 is x^2+y^2-2x-4y+4=0 x^2+y^2-2x-4y+5=0 x^2+y^2=5 (x-3)^2+(y-4)^2=5

Find the equation of the circle which has radius 5 units and which is tangent to the line 3x+4y-16=0 at the point (4, 1).

The radius of the circle which has normals xy-2x-y+2=0 and a tangent 3x+4y-6=0 is