संयुग्मी ज्ञात कीजिए:
`((1+i)(2+i)^(2))/(3+4i)`

(1)/(1-2i)+(3)/(1+4i)

Show that ((2-i)^(2))/(3+4i)=1

Simplify : (1+i)(2+3i)(3+4i)(4+5i) .

(v) (1-i) ^ (2) (1 + i) - (3-4i) ^ (2)

Find the modulus of ((3+2i) (1+i) (2+3i))/((3+4i) (4+5i))

Show that (1- 2i )/( 3 - 4i ) + (1 + 2i )/( 3 + 4i ) is real.

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Simplify : (i+i^(2)+i^(3)+i^(4))/(1+i)

Simplify [ (1)/(1 - 2i ) + (3)/( 1 + i ) ][ ( 3 + 4i )/( 2 - 4i ) ]