An ellipse is sliding along the coordinate axes. If the foci of the ellipse are (1, 1) and (3, 3), then the area of the director circle of the ellipse (in square units) is `2pi` (b) `4pi` (c) `6pi` (d) `8pi`

An ellipse sliding along coordinate axes.If the foci of ellipse are (1,1) and (3,3) .Then which of the following is/are correct? Radius of director circle of ellipse is 2sqrt(2) Length of major axis of ellipse is 2sqrt(5) Length of minor axis of ellipse is sqrt(3) Length of major axis of ellipse is

An ellipse passes through the point (2,3) and its axes along the coordinate axes, 3x +2y -1 = 0 is a tangent to the ellipse, then the equation of the ellipse is

sin^(-1)(0) is equal to : (a) 0 (b) pi/6 (c) pi/2 (d) pi/3

The eccentricity of an ellipse with centre at the orgin and axes along the coordinate axes , is 1/2 if one of the directrices is x=4, the equation of the ellipse is

The eccentric angle of a point on the ellipse x^2/6 + y^2/2 = 1 whose distance from the centre of the ellipse is 2, is (A) pi/4 (B) 7pi/6 (C) 3pi/2 (D) 5pi/3

A circle is inscribed in a square of side 14m. The ratio of the area of the circle and that of the square is pi:3 (b) pi:4 pi:2 (d) pi:1

An ellipse intersects the hyperbola 2x^2-2y =1 orthogonally. The eccentricity of the ellipse is reciprocal to that of the hyperbola. If the axes of the ellipse are along the coordinate axes, then (b) the foci of ellipse are (+-1, 0) (a) equation of ellipse is x^2+ 2y^2 =2 (d) the foci of ellipse are (t 2, 0) (c) equation of ellipse is (x^2 2y)

If the foci of an ellipse are (0,+-1) and the minor axis is of unit length,then find the equation of the ellipse.The axes of ellipse are the coordinate axes.

If the area of a square is same as the area of the circle, then the ratio of their perimeters, in terms of pi , is (a) pi\ :sqrt(3) (b) 2\ :sqrt(pi) (c) 3\ :pi (d) pi\ :sqrt(2)

If A represents the area of the ellipse 3x^(2)+4xy+3y^(2)=1, then the value of (3sqrt(5))/(pi)A is