The lines parallel to the normal to the curve `x y=1` is/are `3x+4y+5=0` (b) `3x-4y+5=0` `4x+3y+5=0` (d) `3y-4x+5=0`

The lines parallel to normal to the curve xy=4 can be(A)3x+4y+7=0 (C) 4x+3y+5=0 ( textrmB ) 3x-4y+5=0(D)3y-4x+7=0

The equation of the plane through the origin and parallel to the plane 3x-4y+5z-6=0 is (A) 3x-4y-5z-6=0 (B) 3x-4y+5z+6=0 (C) 3x-4y_5z=0 (D) 3x+4y-5z+6=0

A line parallel to the line x-3y=2 touches the circle x^(2)+y^(2)-4x+2y-5=0 at the point

2x + 3y = 0 , 3 x + 4y = 5 .

Find the distance between the parallel lines 3x-4y+7=0 and 3x-4y+5=0

The point at which the normal to the curve y = x+(1)/(x), x gt 0 is perpendicular to the line 3x – 4y – 7 = 0 is:

The equation of normal to the curve y=6-x^(2), where the normal is parallel to the line x-4y+3=0 is

3x+4y-5=0 x-y+3=0

The perimeter of a parallelogram whose sides are represented by the lines x+2y+3=0 , 3x+4y-5=0,2x+5=0 and 3x+4y-10=0 is equal to