lf the eccentricity of the hyperbola `x^2-y^2(sec)alpha=5` is `sqrt3` times the eccentricity of the ellipse `x^2(sec)^2alpha+y^2=25,` then a value of `alpha` is : (a) `pi/6` (b) `pi/4` (c) `pi/3` (d) `pi/2`

If the eccentricity of the hyperbola x^(2)-y^(2)(sec)alpha=5 is sqrt(3) xx the eccentricity of the ellipse x^(2)(sec)^(2)alpha+y^(2)=25, then a value of alpha is : (a) (pi)/(6) (b) (pi)/(4) (c) (pi)/(3) (d) (pi)/(2)

If the eccentricity of the hyperbola x^(2)-y^(2)sec^(2)alpha=5 is sqrt3 times the eccentricity of the ellipse x^(2)sec^(2)alpha+y^(2)=25 , then tan^(2)alpha is equal to

If the eccentricity of the hyperbola x^(2)-y^(2)sec^(2)theta=4 is sqrt3 times the eccentricity of the ellipse x^(2)sec^(2)theta+y^(2)=16 , then the value of theta equals

It the eccentricity of the hyerbola x^(2)-y^(2)cos ce^(2) alpha = 25 is sqrt5 time the eccentricity of the ellipse x^(2)cos ce^(2) alpha + y^(2) = 5 , then alpha is equal to :

If the eccentricity of the hyperbola x^(2)-y^(2)sec^(2)alpha=5 is sqrt(3) xx the eccentricity the ellipse x^(2)sec^(2)alpha+y^(2)=25 then alpha=(pi)/(6) b.(pi)/(4) c.(pi)/(3) d.(pi)/(2)

If the eccentricity of the hyperbola x^(2) - y^(2) sec^(2)theta = 4 is sqrt3 time the eccentricity of the ellipse x^(2)sec^(2)theta+y^(2) = 16 , then the volue of theta equal

For some theta in(0,(pi)/(2)) ,if the eccentric of the hyperbola x^(2)-y^(2)sec^(2)theta=10 is sqrt(5) times the eccentricity of the ellipse, x^(2)sec^(2)theta+y^(2)=5 ,then the length of the latus rectum of the ellipse

if 2sec2alpha=tan beta+cot beta then one of the value of alpha+beta is (A) pi (B) npi- pi/4, n in ZZ (C) pi/4 (D) pi/2

If 0 lt alpha lt (pi)/(2) and the eccentricity of the ellipse x^(2) tan^(2) alpha + y^(2) sec^(2) alpha = 1 is 1//2 , then alpha