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he number N=(1/(log2pi)+1/(log6pi)) is l...

he number `N=(1/(log_2pi)+1/(log_6pi))` is less then

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he number N=((1)/(log_(2)pi)+(1)/(log_(6)pi)) is less then

The value of 1/(log_3pi)+1/(log_4pi) is

The value of (1)/(log_(3)pi)+(1)/(log_(4)pi) is

The value of (1)/(log_(3)pi) + (1)/(log_(4)pi) is

Prove that 1/(log_2 pi) + 1/(log_(6)pi) > 2 .

if (1)/(log_(3)pi)+(1)/(log_(4)pi)>x then x be