A parabola is drawn with focus at (3,4) and vertex at the focus of the parabola `y^2-12x-4y+4=0`. The equation of the parabola is

A parabola is drawn with its focus at (3,4) and vertex at the focus of the parabola y^(2)-12x-4y+4=0. The equation of the parabola is: (1)x^(2)-6x-8y+25=0 (2) y^(2)-8x-6y+25=0(3)x^(2)-6x+8y-25=0(4)x^(2)+6x-8y-25=0

Find the focus of the parabola x^2=4y

The focus of the parabola y^(2)-4y-x +3=0 is

The focus of the parabola y^(2)-4y-8x-4=0 is

The focus of the parabola y^(2)-4y-8x-4=0 is

The focus of the parabola y^(2)-4y-8x+4=0 is,

The focus of the parabola y^(2)-4y-8x+4=0 is,

The focus of the parabola y^(2)-4 y-8 x+4=0 is

The focus of the parabola y^2=x+4y+3 , is :