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10 " mL of " NaHC(2)O(4) is oxidised by ...

10 " mL of " `NaHC_(2)O_(4)` is oxidised by 10 " mL of " 0.02 M `MnO_(4)^(ɵ)`. Hence, 10 " mL of " `NaHC_(2)O_(4)` is neutralised by

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100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic medium ( MnO_(4)^(-) reduced to Mn^(+2) ) 100 mL of same H_(2)O_(2) is oxidized by v mL of 1M KMnO_(4) in basic medium ( MnO_(4)^(-) reduced to MnO_(2) ). Find the value of v:

100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic medium ( MnO_(4)^(-) reduced to Mn^(+2) ) 100 mL of same H_(2)O_(2) is oxidized by v mL of 1M KMnO_(4) in basic medium ( MnO_(4)^(-) reduced to MnO_(2) ). Find the value of v:

100mL of H_2O_2 is oxidised by 100mL of 0.01M KMnO_4 in acidic medium (MnO_4^(ɵ) reduced to Mn^(2+) ). 100mL of the same H_2O_2 is oxidised by VmL of 0.01M KMnO_4 in basic medium. Hence V is

100mL of H_2O_2 is oxidised by 100mL of 0.01M KMnO_4 in acidic medium (MnO_4^(ɵ) reduced to Mn^(2+) ). 100mL of the same H_2O_2 is oxidised by VmL of 0.01M KMnO_4 in basic medium. Hence V is

100mL of H_2O_2 is oxidised by 100mL of 0.01M KMnO_4 in acidic medium (MnO_4^(ɵ) reduced to Mn^(2+) ). 100mL of the same H_2O_2 is oxidised by VmL of 0.01M KMnO_4 in basic medium. Hence V is