prove that `sintheta.sec3theta+sin3theta.sec3^2theta+sin3^2theta.sec3^3theta+ u p ton` terms `=1/2[tan3^ntheta-tantheta]`

prove that sinthetadotsec3theta+sin3theta,sec3^2theta+sin3^2thetadotsec3^3theta+ u p ton terms =1/2[tan3^ntheta-tantheta]

prove that sinthetadotsec3theta+sin3theta,sec3^2theta+sin3^2thetadotsec3^3theta+ u p ton terms =1/2[tan3^ntheta-tantheta]

prove that sinthetadotsec3theta+sin3theta,sec3^2theta+sin3^2thetadotsec3^3theta+ u p ton terms =1/2[tan3^ntheta-tantheta]

prove that sin theta*sec3 theta+sin3 theta,sec3^(2)theta+sin3^(2)theta*sec3^(3)theta+... upto n terms =(1)/(2)[tan3^(n)theta-tan theta]

Prove that: sectheta sec 2theta+sec2thetasec3theta+sec3theta.sec4theta+…to n terms = 1/(sintheta) [tan(n+1)theta-tantheta]

Prove that: sectheta sec 2theta+sec2thetasec3theta+sec3theta.sec4theta+…to n terms = 1/(sintheta) [tan(n+1)theta-tantheta]

The sum of the series, sin theta sec(3theta)+sin 3theta sec(3^(2)theta)+sin(3^(2)theta)sec(3^(3)theta)+……. upto n terms, is

If tan theta+sec theta=3/2 then sin theta=

Prove that tan2^ntheta/(tantheta) =(1+sec2theta)(1+sec2^2theta) ....(1+sec2^ntheta)

If sec theta+tan theta=2/3 then sin theta=