A ball of mass 0.2 kg rests on a vertical post of height 5 m. A bullet of mass 0.01 kg, travelling with a velocity `V m//s` in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently. The ball hits the ground at a distance of 20 m and the bullet at a distance of 100 m from the foot of the post. The velocity V of the bullet is

A ball of mass 0.2 kg rests on a vertical post of height 5m. A bullet of mass 0.01 kg, travelling with a velocity v m/s in a horizontal direction, hits the centre of the ball. After the collision, the ball and ullet travel independently. The ball hits the ground at a distance of 20 m and the bullet at a distance of 100m from the foot of the post. the initial velocity v of the bullet is

A ball of mass 0.2 kg moves with a velocity of 20m//sec and it stops in 0.1 sec , then the force on the ball is

A ball of mass 0.2 kg moves with a velocity of 20m//sec and it stops in 0.1 sec , then the force on the ball is

A ball of mass 0.2 kg moves with a velocity of 20m//sec and it stops in 0.1 sec , then the force on the ball is

A small ball with mass M = 0.2 kg rests on top of a vertical column with height h = 5 m . A bullet with mass m = 0.01 kg , moving with velocity v_(0) = 500 m//s , passes horizontally through the center of the ball. The ball reaches the ground at a horizontal distance s = 20 m from the column. Where does the bullet reach the ground? What part of the kinetic energy of the bullet was converted into heat when the bullet passed through the ball? Neglect resistance of the air. Assume that g = 10 m//s^(2) .

A ball of mass 5 kg travelling with velocity of 15 cm/s makes a head on collision with another ball of mass 1 kg which is at rest. After the collision, the speed of the lighter ball is

A ball of mass 5 kg travelling with velocity of 15 cm/s makes a head on collision with another ball of mass 1 kg which is at rest. After the collision, the speed of the lighter ball is

A bullet of mass 0.01 kg travelling at a speed of 500 m/s strikes a block of mass 2 kg, which is suspended by a string of length 5 m. The centre of gravity of the block is found to rise a vertical distance of 0.1 m. The speed of the bullet after it emerges from the block will be -