A block of mass `5 kg` is initially at rest on a rough horizontal surface. A force of `45 N` acts over a distance of `2 m`. The force of friction acting on the block is `25 N`. The final kinetic energy of the block is

A block of mass 2 kg, initially at rest on a horizontal floor, is now acted upon by a horizontal force of 10 N . The coefficient of friction between the block and the floor is 0.2. If g = 10 m//s^(2) , then :

A 10 kg block is initially at rest on a rough horizontal surface. A horizontal force of 60 N is required to set the block in motion . After it is in motion , a horizontal force of 50 N is required to keep the block moving with constant velocity . The ratio coefficient of static and kinetic friction is

A block of mass 5kg is resting on a rough surface as shown in the figure. It is acted upon by a force of F towards right. Find frictional force acting on block when 25N.

A block of mass 20kg is placed on a rough horizontal plane and a horizontal force of 12N is applied. If coefficient of friction is 0.1 the frictional force acting on it is,

A block of mass 10kg is placed on a rough horizontal surface having coefficient of friction mu=0.5 . If a horizontal force of 100N is acting on it, then acceleration of the block will be.

A block of mass 10kg is placed on a rough horizontal surface having coefficient of friction mu=0.5 . If a horizontal force of 100N is acting on it, then acceleration of the block will be.

A block of mass 10kg is placed on a rough horizontal surface having coefficient of friction mu=0.5 . If a horizontal force of 100N is acting on it, then acceleration of the will be.

A block of mass 10kg is placed on a rough horizontal surface having coefficient of friction mu=0.5 . If a horizontal force of 100N is acting on it, then acceleration of the will be.