In Ostwal's process for the manufacture of nitric acid the first step involves the oxidation of ammonia gas by oxygen gas to give nitric oxide gas and steam. What is the maximum weight of nitric oxide that can be obtained starting only with 10.00 g of ammonia and 20.00 g of oxygen.

Ammonia is oxised by oxygen to give nitric oxide and water. The weight of water produced per gram of nitric oxide is 0.1 xx xg . What is value of d.

20 ml of nitric oxide combines with 10 ml of oxygen at STP to give NO_(2) . The final volume will be

When potassium dichromate is heated to a white heat, it decomposes to give pottassium chromate, chromic oxide and oxygen gas. The number of moles of oxygen gas liberated in the decomposi- tion process are

Dihydrogen gas used in Haber's process is produced by reacting methane from natural gas with high temperature steam. The first stage of two stage reaction involves the formation of CO and H_(2) . In second stage , CO formed in first stage is reacted with more steam in water gas shift reaction. CO(g)+H_(2)OhArrCO_(2)(g)+H_(2)(g) If a reaction vessel at 400^(@)C is charged with an equimolar mixtureof CO and steam such that p_(CO)=p_(H_(2)P=4.0 bar, what will be the partial pressure of H_(2) at equilibrium ? K_(p)=10.1 at 400^(@)C

An organic compound (A) of molecular weight 135 on boiling with NaOH evolves a gas which gives white dense fumes on bringing a rod dipped in HCl near it. The alkaline solution thus obtained on acidification gives the precipitate of a compound (B) having molecular weight 136. Treatment of (A) with HNO_2 also yeilds (B), whereas its treatment with Br_2//KOH gives (C). compound (C) reacts with cold HNO_2 to give(D), which gives red colour with ceric ammonium nitrate. On the other hand(E) an isomer of (A) on boiling with dil HCl gives an acid (F), having molecular weight 136. On oxidation followed by heating, (F) gives an anhydride (G) which condenses with benzene in presence of AlCl_3 to give anthraquinone. IUPAC name of compound (B) is

An organic compound (A) of molecular weight 135 on boiling with NaOH evolves a gas which gives white dense fumes on bringing a rod dipped in HCl near it. The alkaline solution thus obtained on acidification gives the precipitate of a compound (B) having molecular weight 136. Treatment of (A) with HNO_2 also yeilds (B), whereas its treatment with Br_2//KOH gives (C). compound (C) reacts with cold HNO_2 to give(D), which gives red colour with ceric ammonium nitrate. On the other hand(E) an isomer of (A) on boiling with dil HCl gives an acid (F), having molecular weight 136. On oxidation followed by heating, (F) gives an anhydride (G) which condenses with benzene in presence of AlCl_3 to give anthraquinone. Structural formula of compound (C) is

An organic compound (A) of molecular weight 135 on boiling with NaOH evolves a gas which gives white dense fumes on bringing a rod dipped in HCl near it. The alkaline solution thus obtained on acidification gives the precipitate of a compound (B) having molecular weight 136. Treatment of (A) with HNO_2 also yeilds (B), whereas its treatment with Br_2//KOH gives (C). compound (C) reacts with cold HNO_2 to give(D), which gives red colour with ceric ammonium nitrate. On the other hand(E) an isomer of (A) on boiling with dil HCl gives an acid (F), having molecular weight 136. On oxidation followed by heating, (F) gives an anhydride (G) which condenses with benzene in presence of AlCl_3 to give anthraquinone. Structrual formula of compound (A) is

Figure Show plot of PV//T versus P for 1.00xx10^(-3) kg of oxygen gas at two different temperatures. (a) What does the dotted plot signify? (b) Which is true: T_(1) gt T_(2) or T_(1) lt T_(2) ? (c) What is the value of PV//T where the curves meet on the y-axis? (d) If we obtained similar plots for 1.00xx10^(-3) kg of hydrogen, would we get the same value of PV//T at the point where the curves meet on the y-axis? If not, what mass of hydrogen yields the same value of PV//T (for low pressure high temperature region of the plot) ? (Molecular mass of H_(2) = 2.02 u, of O_(2) = 32.0 u, R= 8.31Jmol^(-1)K^(-1).)