Comment on the reactions of dihydrogen with (i) chloride (ii) sodium, and (iii) copper (II) oxide.

Explanation

(i) Dihydrogen reduces chlorine into chloride (`Cl^(-1)`) ion and itself gets oxidised to `H^(+)` ion by chlorine to form hydrogen chloride. An electron pair shared between H and Cl leading to the formation of a covalent molecule.
(ii) Dihydrogen is reduced by sodium to form NaH. An electron is transferred rom Na toH leading to the formation of an ionic compound `Na^(+)H^(-)`.
(ii) Dihydrogen reduces copper (II) oxide to copper in zero oxidation state and itself gets oxidised to `H_(2)O`, which is a covalent molecule.