During estimation of nitrogen present in an organic compound by Kjeldahl’s method, the ammonia evolved from 0.5 g of the compound in Kjeldahl’s estimation of nitrogen, neutralized 10 mL of `1 M H_(2)SO_(4)`. Find out the percentage of nitrogen in the compound.

Explanation

1 M of 10 mL `H_(2)SO_(4)=1M` of 20 mL `NH_(3)` 1000 mL of 1M ammonia contains 14 g nitrogen
20 mL of 1M ammonia contains `(14xx20)/(1000)g` nitrogen
Percentage of nitrogen = `(14xx20xx100)/(1000xx0.5)=56.0%`