The point on the line `(x-2)/1=(y+3)/(-2)=(z+5)/(-2)` at a distance of 6 from the point `(2,-3,-5)` is a. `(3,-5,-3)` b. `(4,-7,-9)` c. `0,2,-1` d. none of these

The point of the line (x-2)/(1)=(y+3)/(-2)=(z+5)/(-2) at a distance of 6 from the point (2,-3,-5) is

Distance of the point of intersection of the line (x-3)/(1)=(y-4)/(2)=(z-5)/(2)and plane x+y+z=2 from the point (3,4,5) is

The distance between the line (x-2)/(1)=(y-3)/(1)=(z-4)/(5) and the plane 2x+3y-z+5=0 is

A point on the line (x-1)/1=(y-2)/2=(z+1)/3 at a distance sqrt(6) from the origin is (A) ((-5)/7, (-10)/7,13/7) (B) (5/7,10/7,(-13)/7) (C) (1,2,-1) (D) (-1,-2,1)

Statement 1: A point on the line (x+2)/3=(y+1)/2=(z-3)/2 at a distance 3sqrt(2) from the point (1,2,3) lies on the lne (x+7)/5=(y+t)/4=(z-2)/1 Statement 2: If d is the distance between the point (-1,-5,-10) and the point of intersectionof the line (x-2)/3=(y+1)/4=(z-2)/12 with the plane x-y+z=5 then d=13

The distance of the point (-3,4) from the line 3x+4y-5=0 is (2)/(5) .

Find the distance of the point of intersection of the line (x-3)/(1)=(y-4)/(2)=(z-5)/(2) and the plane x+y+z=17 from the point (3,4,5) .

The point on the circle (x-3)^2 + (y-4)^2 = 4 which is at least distance from the circle x^2 + y^2 = 1 is : (A) (3/5, 4/5) (B) (9/5, 12/5) (C) (9, 12) (D) none of these

Find the distance of the point (2, 3, -5) from the plane x+2y-2z-9=0.