Let z1 ,z2 in c and z1 != z2 Show that t...

Let `z_1 ,z_2 in c` and `z_1 != z_2` Show that the equation of any circle passing through `z_1` and `z_2` is `|2z-z_1-z_2|-|z_1-z_2|+lambda Im((z-z_1)/(z_2-z_1))=0` where `lambda in R`

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