Perpendiculars are drawn from points on the line `(x+2)/2=(y+1)/(-1)=z/3` to the plane `x + y + z=3` The feet of perpendiculars lie on the line (a) `x/5=(y-1)/8=(z-2)/(-13)` (b) `x/2=(y-1)/3=(z-2)/(-5)` (c) `x/4=(y-1)/3=(z-2)/(-7)` (d) `x/2=(y-1)/(-7)=(z-2)/5`

Perpendicular are drawn from points on the line (x+2)/(2)=(y+1)/(-1)=(z)/(3) to the plane x+y+z=3 . The feet of perpendiculars lie on the line.

Perpendiculars are drawn from points on the line (x+2)/(2)=(y+1)/(-1)=(z)/(3) to the plane x+y+z=3 The feet of perpendiculars lie on the line (a) (x)/(5)=(y-1)/(8)=(z-2)/(-13) (b) (x)/(2)=(y-1)/(3)=(z-2)/(-5)(d)(x)/(4)=(y-1)/(-7)=(z-2)/(5)(d)(x)/(2)=(y-1)/(-7)=(z-2)/(5)

The line (x-3)/1=(y-4)/2=(z-5)/2 cuts the plane x+y+z=17 at

The equation of the line through (1,1,1) and perpendicular to the plane 2x+3y-z=5 is (A) (x-1)/2=(y-1)/3=z-1 (B) (x-1)/2=(y-1)/3=(z-1)/(-1) (C) (x-1)/2=(y-1)/3=(z-1)/(5) (D) (x-1)/2=(y-1)/(-3)=z-1

The image of the line (x-1)/(3)=(y-3)/(1)=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1)(x+3)/(3)=(y-5)/(1)=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/(5) (3) (x-3)/(3)=(y+5)/(1)=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/(5)

The lines (x)/(1)=(y)/(2)=(z)/(3)and(x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

Image of line (x - 2)/3 = (y - 1)/1 = (z - 1)/(-4) in the plane x + y + z = 7 is

Reflection of the line (x-1)/(-1)=(y-2)/(3)=(z-3)/(1) in the plane x+y+z=7 is