For a hypothetical reaction, `A rarr L` the rate expression is
rate `=-(dC_(A))/(dt)`

For a hypothetical reaction AtoL the rate expression is rate =-(dC_(A))/(dt)

For a reaction A+B rarr products The rate law expression is

The rate and mechamical reaction are studied in chemical kinetics. The elementary reactions are single step reaction having no mechanism. The order of reaction and molecularity are same for elementary reactions. The rate of forward reaction aA + bBrarr cC+dD is given as: rate =((dx)/(dt))=-1/a(d[A])/(dt)=-1/b(d[B])/(dt)=1/c(d[C])/(dt)=1/d(d[D])/(dt) or expression can be written as : rate =K_(1)[A]^(a)[B]^(b)-K_(2)[C]^(c )[D]^(d) . At equilibrium, rate = 0 . The constants K, K_(1), K_(2) are rate constants of respective reaction. In case of reactions governed by two or more steps reaction mechanism, the rate is given by the slowest step of mechanism. For a hypothetical reaction aA+bBrarr Product, the rate law is: rate =K[A]^(x)[B]^(y) , then:

For a hypothetical reaction aA + bB rarr Product, the rate law is: rate = K[A]^(x)[B]^(y) , then

For a hypothetical reaction aA + bB rarr Product, the rate law is: rate = K[A]^(x)[B]^(y) , then which of the following relation is possible-

For the hypothetical reaction 2A rarr3C , the reaction rate r in terms of the rate of change of the concentration is given by

For the hypothetical reaction 2A rarr3C , the reaction rate r in terms of the rate of change of the concentration is given by