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Let A = {p,q,r,s},B={p,q,r} and C= {q,S}...

Let A = {p,q,r,s},B={p,q,r} and C= {q,S} . Find all sets X such that :
(i) `XsubBandXsubC`
(ii) `XsubAandX!inB`.

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The correct Answer is:
To solve the question, we need to find all sets \( X \) that satisfy the given conditions. We will address each part of the question step by step. ### Given Sets: - \( A = \{p, q, r, s\} \) - \( B = \{p, q, r\} \) - \( C = \{q, s\} \) ### Part (i): Find all sets \( X \) such that \( X \subseteq B \) and \( X \subseteq C \). 1. **Identify subsets of set B**: - The subsets of \( B \) are: - \( \emptyset \) (the empty set) - \( \{p\} \) - \( \{q\} \) - \( \{r\} \) - \( \{p, q\} \) - \( \{p, r\} \) - \( \{q, r\} \) - \( \{p, q, r\} \) 2. **Identify subsets of set C**: - The subsets of \( C \) are: - \( \emptyset \) - \( \{q\} \) - \( \{s\} \) - \( \{q, s\} \) 3. **Find common subsets**: - We need to find subsets that are common to both \( B \) and \( C \). - The only common element between \( B \) and \( C \) is \( q \). - Therefore, the possible sets \( X \) that are subsets of both \( B \) and \( C \) are: - \( \emptyset \) - \( \{q\} \) ### Conclusion for Part (i): The sets \( X \) that satisfy \( X \subseteq B \) and \( X \subseteq C \) are: - \( X = \emptyset \) - \( X = \{q\} \) ### Part (ii): Find all sets \( X \) such that \( X \subseteq A \) and \( X \not\subseteq B \). 1. **Identify subsets of set A**: - The subsets of \( A \) are: - \( \emptyset \) - \( \{p\} \) - \( \{q\} \) - \( \{r\} \) - \( \{s\} \) - \( \{p, q\} \) - \( \{p, r\} \) - \( \{q, r\} \) - \( \{p, s\} \) - \( \{q, s\} \) - \( \{r, s\} \) - \( \{p, q, r\} \) - \( \{p, q, s\} \) - \( \{p, r, s\} \) - \( \{q, r, s\} \) - \( \{p, q, r, s\} \) 2. **Determine which subsets are not in B**: - The elements of \( B \) are \( \{p, q, r\} \). - Therefore, any subset of \( A \) that contains \( s \) will not be a subset of \( B \). - The valid subsets of \( A \) that contain \( s \) are: - \( \{s\} \) - \( \{q, s\} \) - \( \{p, s\} \) - \( \{p, q, s\} \) - \( \{r, s\} \) - \( \{p, r, s\} \) - \( \{q, r, s\} \) - \( \{p, q, r, s\} \) ### Conclusion for Part (ii): The sets \( X \) that satisfy \( X \subseteq A \) and \( X \not\subseteq B \) are: - \( X = \{s\} \) - \( X = \{q, s\} \) - \( X = \{p, s\} \) - \( X = \{p, q, s\} \) - \( X = \{r, s\} \) - \( X = \{p, r, s\} \) - \( X = \{q, r, s\} \) - \( X = \{p, q, r, s\} \) ### Final Answer: 1. For part (i): \( X = \emptyset \) or \( X = \{q\} \) 2. For part (ii): \( X = \{s\}, \{q, s\}, \{p, s\}, \{p, q, s\}, \{r, s\}, \{p, r, s\}, \{q, r, s\}, \{p, q, r, s\} \)
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