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Show that AcapB=AcapC need not imply B=C...

Show that `AcapB=AcapC` need not imply B=C.

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Statement-1 Let A and B be the two events, such that P(AcupB)=P(AcapB) , then P(AcapB')=P(A'capB)=0 Statement-2 Let A and B be the two events, such that P(AcupB)=P(AcapB), then P(A)+P(B)=1

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If A , B and C are any three sets , then prove that : Acap(B-C)=(AcapB)-(AcapC) (ii) Acap(BDeltaC)=(AcapB)Delta(AcapC) .