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Let S={x|x is a positive multiple of 3 ...

Let S={x|x is a positive multiple of 3 less than 100}, P= {x|x is a prime number less than 20}.

A

34

B

41

C

33

D

30

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the number of elements in the sets \( S \) and \( P \) and then add these two quantities together. Let's break it down step by step. ### Step 1: Define the set \( S \) The set \( S \) is defined as: \[ S = \{ x \mid x \text{ is a positive multiple of 3 less than 100} \} \] To find the elements of \( S \), we list the positive multiples of 3 that are less than 100: - The first positive multiple of 3 is 3. - The next multiples are 6, 9, 12, ..., up to the largest multiple of 3 that is less than 100. The largest multiple of 3 less than 100 can be found by dividing 99 by 3: \[ 99 \div 3 = 33 \] Thus, the multiples of 3 less than 100 are: \[ S = \{ 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99 \} \] ### Step 2: Count the elements in set \( S \) To count the number of elements in \( S \), we can observe that the multiples of 3 form an arithmetic sequence where: - First term \( a = 3 \) - Common difference \( d = 3 \) - Last term \( l = 99 \) The number of terms \( n \) in an arithmetic sequence can be calculated using the formula: \[ n = \frac{l - a}{d} + 1 \] Substituting the values: \[ n = \frac{99 - 3}{3} + 1 = \frac{96}{3} + 1 = 32 + 1 = 33 \] So, \( n(S) = 33 \). ### Step 3: Define the set \( P \) The set \( P \) is defined as: \[ P = \{ x \mid x \text{ is a prime number less than 20} \} \] The prime numbers less than 20 are: \[ P = \{ 2, 3, 5, 7, 11, 13, 17, 19 \} \] ### Step 4: Count the elements in set \( P \) Counting the elements in \( P \): - The prime numbers listed are 2, 3, 5, 7, 11, 13, 17, and 19. - There are a total of 8 prime numbers. So, \( n(P) = 8 \). ### Step 5: Add the number of elements in sets \( S \) and \( P \) Now we add the number of elements in both sets: \[ n(S) + n(P) = 33 + 8 = 41 \] ### Final Answer The final answer is: \[ \text{The number of elements in } S + P = 41 \] ---
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