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What is n(AuuBuuC)?...

What is `n(AuuBuuC)?`

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To find \( n(A \cup B \cup C) \), we will use the principle of inclusion-exclusion. The formula for the number of elements in the union of three sets \( A \), \( B \), and \( C \) is given by: \[ n(A \cup B \cup C) = n(A) + n(B) + n(C) - n(A \cap B) - n(A \cap C) - n(B \cap C) + n(A \cap B \cap C) \] ### Step-by-Step Solution: 1. **Identify the Number of Elements in Each Set**: - Let \( n(A) \) be the number of elements in set \( A \). - Let \( n(B) \) be the number of elements in set \( B \). - Let \( n(C) \) be the number of elements in set \( C \). 2. **Identify the Number of Elements in Intersections**: - Let \( n(A \cap B) \) be the number of elements common to both sets \( A \) and \( B \). - Let \( n(A \cap C) \) be the number of elements common to both sets \( A \) and \( C \). - Let \( n(B \cap C) \) be the number of elements common to both sets \( B \) and \( C \). - Let \( n(A \cap B \cap C) \) be the number of elements common to all three sets \( A \), \( B \), and \( C \). 3. **Apply the Inclusion-Exclusion Formula**: Substitute the values into the inclusion-exclusion formula: \[ n(A \cup B \cup C) = n(A) + n(B) + n(C) - n(A \cap B) - n(A \cap C) - n(B \cap C) + n(A \cap B \cap C) \] 4. **Calculate the Result**: - Perform the arithmetic operations based on the values you have for each of the sets and their intersections. 5. **Conclusion**: - The result from the above calculation will give you the total number of unique elements in the union of sets \( A \), \( B \), and \( C \).
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