Home
Class 11
MATHS
Find the locus of the points which are e...

Find the locus of the points which are equidistant from the points (1,2,3) and (3,2,11).

Text Solution

Verified by Experts

The correct Answer is:
`x-2z=0
Promotional Banner

Topper's Solved these Questions

  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    MODERN PUBLICATION|Exercise EXERCISE 12(B) (LONG ANSWER TYPE QUESTIONS-I)|12 Videos

  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    MODERN PUBLICATION|Exercise EXERCISE|4 Videos

  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    MODERN PUBLICATION|Exercise EXERCISE 12(A) (SHORT ANSWER TYPE QUESTIONS)|8 Videos

  • CONIC SECTIONS

    MODERN PUBLICATION|Exercise CHAPTER TEST 11|12 Videos

  • LIMITS AND DERIVATIVES

    MODERN PUBLICATION|Exercise CHECK YOUR UNDERSTANDING|10 Videos

Similar Questions

Explore conceptually related problems

Find the locus of the point which is equidistant from the points (1,-2,3) and (-3,4,2).

Find the locus of the point which is equidistant from the points A(0,2,3) and B(2,-2,1)

Find the locus of the point which is equidistant from the points A(0,2,3) and (2,-2,1) .

Find the locus of a point which is equidistant from the points (-1,2,3) and (3,2,1)

The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is

Find the equation of the set of points which are equidistant from the points (1,2,3) and (3,2,-1) .

Find the equation of the set of points which are equidistant from the points (1,2,3) and (3,2,-1)

The locus of the point which is equidistant from the points (2, -2, 1) and (0, 2, 3) is

Find the equation of the set of points which are equidistant from the points (1,-2,3) and (3,-2,-1)

The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is (A) x+y=0 (B) x+y=7 (C) 4x+4y=38 (D) x+y=1