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One card is drawn from a well shuffled deck o 52 cards. If each outcome is equally likely, calculate the probabilty that the card will be:
(i)a diamond
(ii) not a diamond
(iii) not an ace
(iv) a black card (i.e.a club or a spade)
v. not a black card.

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To solve the problem step by step, we will calculate the probabilities for each of the specified cases when one card is drawn from a well-shuffled deck of 52 cards. ### Step-by-Step Solution: 1. **Probability of drawing a diamond:** - In a standard deck of cards, there are 13 diamonds. - The total number of cards is 52. - The probability \( P(\text{Diamond}) \) is given by: \[ P(\text{Diamond}) = \frac{\text{Number of Diamonds}}{\text{Total Number of Cards}} = \frac{13}{52} = \frac{1}{4} \] 2. **Probability of not drawing a diamond:** - The probability of not drawing a diamond can be calculated using the complement rule: \[ P(\text{Not Diamond}) = 1 - P(\text{Diamond}) = 1 - \frac{1}{4} = \frac{3}{4} \] - Alternatively, since there are 39 cards that are not diamonds (52 total cards - 13 diamonds): \[ P(\text{Not Diamond}) = \frac{39}{52} = \frac{3}{4} \] 3. **Probability of not drawing an ace:** - There are 4 aces in a standard deck of cards. - The probability of drawing an ace is: \[ P(\text{Ace}) = \frac{4}{52} \] - Thus, the probability of not drawing an ace is: \[ P(\text{Not Ace}) = 1 - P(\text{Ace}) = 1 - \frac{4}{52} = \frac{48}{52} = \frac{12}{13} \] 4. **Probability of drawing a black card (club or spade):** - There are 26 black cards in total (13 clubs + 13 spades). - The probability of drawing a black card is: \[ P(\text{Black Card}) = \frac{26}{52} = \frac{1}{2} \] 5. **Probability of not drawing a black card:** - The probability of not drawing a black card can also be calculated using the complement rule: \[ P(\text{Not Black Card}) = 1 - P(\text{Black Card}) = 1 - \frac{1}{2} = \frac{1}{2} \] - Alternatively, since there are 26 red cards (hearts + diamonds): \[ P(\text{Not Black Card}) = \frac{26}{52} = \frac{1}{2} \] ### Summary of Probabilities: - (i) Probability of drawing a diamond: \( \frac{1}{4} \) - (ii) Probability of not drawing a diamond: \( \frac{3}{4} \) - (iii) Probability of not drawing an ace: \( \frac{12}{13} \) - (iv) Probability of drawing a black card: \( \frac{1}{2} \) - (v) Probability of not drawing a black card: \( \frac{1}{2} \)
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