If `P(A)=0.15, P(B)=0.35, P(barA)+P(barB)` is equal to

Options

A. 0
B. 1
C. 1.5
D. 8

Answer

To solve the problem, we need to find \( P(\bar{A}) + P(\bar{B}) \) given that \( P(A) = 0.15 \) and \( P(B) = 0.35 \).

### Step-by-Step Solution:

1. **Find \( P(\bar{A}) \)**:
- The probability of the complement of event A, denoted as \( P(\bar{A}) \), is calculated using the formula:
\[ P(\bar{A}) = 1 - P(A) \]
- Substituting the value of \( P(A) \):
\[ P(\bar{A}) = 1 - 0.15 = 0.85 \]

2. **Find \( P(\bar{B}) \)**:
- Similarly, the probability of the complement of event B, denoted as \( P(\bar{B}) \), is calculated as:
\[ P(\bar{B}) = 1 - P(B) \]
- Substituting the value of \( P(B) \):
\[ P(\bar{B}) = 1 - 0.35 = 0.65 \]

3. **Add \( P(\bar{A}) \) and \( P(\bar{B}) \)**:
- Now, we add the probabilities of the complements:
\[ P(\bar{A}) + P(\bar{B}) = 0.85 + 0.65 \]
- Performing the addition:
\[ P(\bar{A}) + P(\bar{B}) = 1.50 \]

### Final Answer:
Thus, \( P(\bar{A}) + P(\bar{B}) = 1.5 \).