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Threecoins are tossed once. Find the pro...

Threecoins are tossed once. Find the probability of getting
(i) 3 heads (ii) 2 heads
(iii) 3 tails.

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To solve the problem of finding the probability of getting 3 heads, 2 heads, and 3 tails when tossing three coins, we can follow these steps: ### Step 1: Determine the Sample Space When tossing 3 coins, each coin has 2 possible outcomes: Heads (H) or Tails (T). The total number of outcomes when tossing 3 coins can be calculated as: \[ \text{Total Outcomes} = 2^n = 2^3 = 8 \] The sample space (S) consists of the following outcomes: - HHH - HHT - HTH - HTT - THH - THT - TTH - TTT ### Step 2: Calculate the Probability of Getting 3 Heads (HHH) To find the probability of getting 3 heads, we identify the favorable outcomes. There is only 1 outcome where all coins show heads: - HHH Thus, the probability \( P(3 \text{ heads}) \) is given by: \[ P(3 \text{ heads}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{1}{8} \] ### Step 3: Calculate the Probability of Getting 2 Heads Next, we count the outcomes with exactly 2 heads. The favorable outcomes are: - HHT - HTH - THH There are 3 outcomes where there are exactly 2 heads. Therefore, the probability \( P(2 \text{ heads}) \) is: \[ P(2 \text{ heads}) = \frac{3}{8} \] ### Step 4: Calculate the Probability of Getting 3 Tails (TTT) Finally, we find the probability of getting 3 tails. There is only 1 outcome where all coins show tails: - TTT Thus, the probability \( P(3 \text{ tails}) \) is: \[ P(3 \text{ tails}) = \frac{1}{8} \] ### Summary of Probabilities - Probability of getting 3 heads: \( P(3 \text{ heads}) = \frac{1}{8} \) - Probability of getting 2 heads: \( P(2 \text{ heads}) = \frac{3}{8} \) - Probability of getting 3 tails: \( P(3 \text{ tails}) = \frac{1}{8} \)
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