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An event 'E' is defined as getting both...

An event 'E' is defined as getting both heads or both tails in a throw of two coins, then find P(E) …………….

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To find the probability of the event 'E', which is defined as getting both heads or both tails in a throw of two coins, we can follow these steps: ### Step 1: Define the Sample Space When we throw two coins, the possible outcomes can be represented as: - HH (both heads) - HT (first head, second tail) - TH (first tail, second head) - TT (both tails) Thus, the sample space \( S \) consists of these outcomes: \[ S = \{ HH, HT, TH, TT \} \] ### Step 2: Count the Total Number of Outcomes The total number of outcomes in the sample space \( S \) is: \[ n(S) = 4 \] ### Step 3: Define the Event 'E' The event 'E' is defined as getting both heads (HH) or both tails (TT). Therefore, we can list the outcomes that satisfy this event: - HH (both heads) - TT (both tails) ### Step 4: Count the Favorable Outcomes Now, we need to count the number of favorable outcomes for event 'E': - The favorable outcomes are: HH and TT. Thus, the number of favorable outcomes \( n(E) \) is: \[ n(E) = 2 \] ### Step 5: Calculate the Probability of Event 'E' The probability \( P(E) \) of event 'E' can be calculated using the formula: \[ P(E) = \frac{n(E)}{n(S)} \] Substituting the values we found: \[ P(E) = \frac{2}{4} = \frac{1}{2} \] ### Final Answer Thus, the probability of getting both heads or both tails in a throw of two coins is: \[ P(E) = \frac{1}{2} \] ---
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