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tan^(-2)tan((3pi)/(4))...

`tan^(-2)tan((3pi)/(4))`

Text Solution

Verified by Experts

The correct Answer is:
`-pi/4`
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Principal value of tan^(-1)[tan((3pi)/(4))] is

tan^(-1)(tan\ (3pi)/(4))

If alpha=tan^(-1)(tan(5 pi)/(4)) and beta=tan^(-1)(-tan(2 pi)/(3)), then 4 alpha=3 beta(b)3 alpha=4 beta(c)alpha-beta=74 alpha=(3 beta)/(12) none of these

tan^(-1)[ tan(-(3 pi)/(4))]

Principal value of tan^(-1)[tan((3pi)/4)] is

tan x+(tan((pi)/(4))+tan x)/(1-tan((pi)/(4))tan x)=2

tan^(-1)(tan(2 pi/(3)))

tan^(-1)("tan"(2pi)/3)