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The total revenue in rupees received fro...

The total revenue in rupees received from the sale of 'x' units of a product is given by:
`R(x)=13x^(2)+26x+20.`
Find the marginal revenue when x = 7

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To find the marginal revenue when \( x = 7 \), we will follow these steps: ### Step 1: Understand the concept of Marginal Revenue Marginal Revenue (MR) is defined as the derivative of the total revenue function \( R(x) \) with respect to \( x \). Mathematically, it is represented as: \[ MR = \frac{dR}{dx} \] ### Step 2: Write down the total revenue function The total revenue function given is: \[ R(x) = 13x^2 + 26x + 20 \] ### Step 3: Differentiate the total revenue function To find the marginal revenue, we need to differentiate \( R(x) \) with respect to \( x \): \[ \frac{dR}{dx} = \frac{d}{dx}(13x^2) + \frac{d}{dx}(26x) + \frac{d}{dx}(20) \] Calculating each term: - The derivative of \( 13x^2 \) is \( 26x \) (using the power rule). - The derivative of \( 26x \) is \( 26 \). - The derivative of a constant \( 20 \) is \( 0 \). Thus, we have: \[ \frac{dR}{dx} = 26x + 26 \] ### Step 4: Substitute \( x = 7 \) into the marginal revenue function Now we will find the marginal revenue when \( x = 7 \): \[ MR = 26(7) + 26 \] Calculating this gives: \[ MR = 182 + 26 = 208 \] ### Conclusion The marginal revenue when \( x = 7 \) is: \[ \boxed{208} \text{ rupees per unit} \] ---
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