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Use differentials, find the approximate value of the following :
`cos""(11pi)/(36)`.

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To find the approximate value of \( \cos\left(\frac{11\pi}{36}\right) \) using differentials, we can follow these steps: ### Step 1: Define the function and the point of approximation Let \( f(x) = \cos(x) \). We want to approximate \( f\left(\frac{11\pi}{36}\right) \). ### Step 2: Choose a nearby point We can choose a nearby point where we know the cosine value exactly. A suitable choice is \( x = \frac{\pi}{3} \) because \( \frac{\pi}{3} = \frac{12\pi}{36} \). ### Step 3: Calculate \( \delta x \) We have: \[ x + \delta x = \frac{11\pi}{36} \] Thus, \[ \delta x = \frac{11\pi}{36} - \frac{\pi}{3} \] To calculate this, we convert \( \frac{\pi}{3} \) to have a common denominator: \[ \frac{\pi}{3} = \frac{12\pi}{36} \] Now substituting: \[ \delta x = \frac{11\pi}{36} - \frac{12\pi}{36} = -\frac{\pi}{36} \] ### Step 4: Calculate \( \frac{df}{dx} \) Next, we need the derivative of \( f(x) \): \[ \frac{df}{dx} = -\sin(x) \] At \( x = \frac{\pi}{3} \): \[ \frac{df}{dx} = -\sin\left(\frac{\pi}{3}\right) = -\frac{\sqrt{3}}{2} \] ### Step 5: Calculate \( \delta f \) Using the formula \( \delta f = \frac{df}{dx} \cdot \delta x \): \[ \delta f = -\frac{\sqrt{3}}{2} \cdot \left(-\frac{\pi}{36}\right) = \frac{\sqrt{3} \cdot \pi}{72} \] ### Step 6: Calculate \( f\left(\frac{11\pi}{36}\right) \) Now we can find \( f\left(\frac{11\pi}{36}\right) \): \[ f\left(\frac{11\pi}{36}\right) \approx f\left(\frac{\pi}{3}\right) + \delta f \] We know \( f\left(\frac{\pi}{3}\right) = \cos\left(\frac{\pi}{3}\right) = \frac{1}{2} \): \[ f\left(\frac{11\pi}{36}\right) \approx \frac{1}{2} + \frac{\sqrt{3} \cdot \pi}{72} \] ### Step 7: Numerical approximation Using \( \pi \approx 3.14 \): \[ \frac{\sqrt{3}}{2} \approx 0.866 \quad \text{and} \quad \frac{3.14}{72} \approx 0.0436 \] Thus, \[ \delta f \approx 0.866 \cdot 0.0436 \approx 0.0378 \] Finally, \[ f\left(\frac{11\pi}{36}\right) \approx \frac{1}{2} + 0.0378 \approx 0.5378 \] ### Conclusion The approximate value of \( \cos\left(\frac{11\pi}{36}\right) \) is approximately \( 0.5378 \). ---
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MODERN PUBLICATION-APPLICATIONS OF DERIVATIVES-EXERCISE 6 (d) (Long Answer Type Questions (I))
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  2. In the following find the approximate values, using differentials : ...

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  3. In the following find the approximate values, using differentials : ...

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  5. Find approximation value of (3.968)^(3/2) using differentials.

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  6. In the following find the approximate values, using differentials : ...

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  7. Find the approximate value of : f(3.02)," where "f(x)=3x^(2)+15x+3

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  8. Find the approximate value of f (5. 001), where f(x)=x^3-7x^2+15.

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  9. Find the approximate change in the volume V of a cube of side x met...

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  10. Find the approximate change in the surface area of a cube of side x...

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  11. If the radius of a sphere is measured as 9 cm with an error of 0.03...

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  12. cos 61^(@), it being given that sin 60^(@) = 0.86603 and 1^(@) = 0.017...

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  13. Find the approximate change in the value of (1)/(x^(2)). when x change...

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  14. Using differentiation, find the approximate value of f(3.01), where f(...

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  15. Use differentials, find the approximate value of the following : sin...

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  16. Use differentials, find the approximate value of the following : cos...

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  17. If y=sinxa n dx change from pi/2to(22)/(14), what is the approximat...

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  18. A circular metal plate expands under heating so that its radius inc...

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  19. Find the percentage error in calculating the surface area of a cubi...

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  20. The radius of a spherical diamond is measured as 6 cm with an error of...

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