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A helicopter is flying along the curve y...

A helicopter is flying along the curve `y=x^(2)+2`. A soldier is placed at the point (3, 2). Find the nearest distance between the solider and the helicopter.

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To find the nearest distance between the soldier located at the point (3, 2) and the helicopter flying along the curve \( y = x^2 + 2 \), we can follow these steps: ### Step 1: Define the Points Let the point on the curve where the helicopter is located be \( (h, h^2 + 2) \). Here, \( h \) represents the x-coordinate of the helicopter's position on the curve. ### Step 2: Write the Distance Formula The distance \( D \) between the soldier at point \( (3, 2) \) and the helicopter at point \( (h, h^2 + 2) \) can be expressed using the distance formula: \[ D = \sqrt{(h - 3)^2 + (h^2 + 2 - 2)^2} \] This simplifies to: \[ D = \sqrt{(h - 3)^2 + (h^2)^2} \] ### Step 3: Minimize the Distance To minimize the distance, we can minimize \( D^2 \) instead, as the square root function is monotonically increasing. Thus, we define: \[ D^2 = (h - 3)^2 + (h^2)^2 \] Expanding this, we get: \[ D^2 = (h - 3)^2 + h^4 = (h^2 - 6h + 9) + h^4 = h^4 + h^2 - 6h + 9 \] ### Step 4: Find the Derivative To find the minimum, we take the derivative of \( D^2 \) with respect to \( h \): \[ \frac{d(D^2)}{dh} = 4h^3 + 2h - 6 \] ### Step 5: Set the Derivative to Zero Setting the derivative equal to zero to find critical points: \[ 4h^3 + 2h - 6 = 0 \] Dividing the entire equation by 2 gives: \[ 2h^3 + h - 3 = 0 \] ### Step 6: Find the Roots To solve \( 2h^3 + h - 3 = 0 \), we can use the Rational Root Theorem or synthetic division. Testing \( h = 1 \): \[ 2(1)^3 + (1) - 3 = 2 + 1 - 3 = 0 \] Thus, \( h = 1 \) is a root. We can factor the polynomial: \[ 2h^3 + h - 3 = (h - 1)(2h^2 + 2h + 3) \] The quadratic \( 2h^2 + 2h + 3 \) has no real roots (discriminant \( < 0 \)), so the only real solution is \( h = 1 \). ### Step 7: Calculate the Minimum Distance Now, substituting \( h = 1 \) back into the distance formula: \[ D^2 = (1 - 3)^2 + (1^2)^2 = (-2)^2 + (1)^2 = 4 + 1 = 5 \] Thus, the minimum distance \( D \) is: \[ D = \sqrt{5} \] ### Final Answer The nearest distance between the soldier and the helicopter is \( \sqrt{5} \). ---
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