Logarithmic function is strictly …………..in `(0, pi)`.

Answer

To determine whether the logarithmic function \( y = \log(x) \) is strictly increasing or decreasing in the interval \( (0, \pi) \), we will follow these steps:

### Step 1: Define the function
We start with the function:
\[ y = \log(x) \]

### Step 2: Differentiate the function
Next, we differentiate the function with respect to \( x \):
\[ \frac{dy}{dx} = \frac{1}{x} \]

### Step 3: Analyze the derivative
Now, we need to analyze the sign of the derivative \( \frac{dy}{dx} \) in the interval \( (0, \pi) \):
- The derivative \( \frac{1}{x} \) is positive for all \( x > 0 \).

### Step 4: Determine the behavior of the function
Since \( \frac{dy}{dx} > 0 \) for all \( x \) in the interval \( (0, \pi) \), we conclude that the function \( y = \log(x) \) is strictly increasing in this interval.

### Final Answer
Thus, we can fill in the blank:
The logarithmic function is strictly **increasing** in \( (0, \pi) \).

---