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Find the two numbers with maximum product and whose sum is 24.

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To find the two numbers with maximum product whose sum is 24, we can follow these steps: ### Step 1: Define the Variables Let the two numbers be \( x \) and \( y \). According to the problem, we have: \[ x + y = 24 \] ### Step 2: Express One Variable in Terms of the Other From the equation \( x + y = 24 \), we can express \( y \) in terms of \( x \): \[ y = 24 - x \] ### Step 3: Write the Product Function The product \( P \) of the two numbers \( x \) and \( y \) can be expressed as: \[ P = x \cdot y = x(24 - x) = 24x - x^2 \] ### Step 4: Differentiate the Product Function To find the maximum product, we need to differentiate \( P \) with respect to \( x \): \[ \frac{dP}{dx} = 24 - 2x \] ### Step 5: Set the Derivative to Zero To find the critical points, set the derivative equal to zero: \[ 24 - 2x = 0 \] Solving for \( x \): \[ 2x = 24 \implies x = 12 \] ### Step 6: Find the Corresponding Value of \( y \) Using the value of \( x \) in the equation for \( y \): \[ y = 24 - x = 24 - 12 = 12 \] ### Step 7: Conclusion The two numbers that give the maximum product are: \[ \text{The numbers are } 12 \text{ and } 12. \] ### Step 8: Verify Maximum Product To confirm that this is a maximum, we can check the second derivative: \[ \frac{d^2P}{dx^2} = -2 \] Since \(\frac{d^2P}{dx^2} < 0\), this indicates that the function has a maximum at \( x = 12 \).
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MODERN PUBLICATION-APPLICATIONS OF DERIVATIVES-NCERT - FILE (Question from NCERT Book) (Exercise 6.5)
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