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The point on the curve x^2=2ywhich is ne...

The point on the curve `x^2=2y`which is nearest to the point (0, 5) is(A) `(2sqrt(2),4)` (B) `(2sqrt(2),0)` (C) (0, 0) (D) (2, 2)

A

`(2sqrt2, 4)`

B

`(2sqrt2,0)`

C

`(0,0)`

D

`(2, 2)`

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MODERN PUBLICATION-APPLICATIONS OF DERIVATIVES-NCERT - FILE (Question from NCERT Book) (Exercise 6.5)
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