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int(2sin2theta-costheta)/(6-cos^2theta-4...

`int(2sin2theta-costheta)/(6-cos^2theta-4sintheta) d theta`

Text Solution

Verified by Experts

The correct Answer is:
`(sin theta-2)+c`
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Knowledge Check

  • int(costheta-cos2theta)/(1-cos theta)d theta=

    A
    `theta+2sin theta+c`
    B
    `theta-2sin theta+c`
    C
    `2theta+2sin theta+c`
    D
    `2theta-2sin theta+c`

  • (sintheta+sin2theta)/(1+costheta+cos2theta) =

    A
    `(1)/(2)tantheta`
    B
    `(1)/(2)cottheta`
    C
    `tantheta`
    D
    `cottheta`

  • int((sintheta+costheta))/sqrt(sin2theta)"d"theta=

    A
    `logabs(costheta-sintheta+sqrt(sin2theta))+c`
    B
    `logabs(sintheta-costheta+sqrt(sin2theta))+c`
    C
    `sin^(-1)(sintheta-costheta)+c`
    D
    `sin^(-1)(sintheta+costheta)+c`

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    int cos2 theta * ln ((cos theta + sin theta) / (cos theta-sin theta)) d theta

    int (cos2theta) . log((costheta+sintheta)/(costheta-sintheta))d theta is equal to

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