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integrate the function x sin x...

integrate the function `x sin x`

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To integrate the function \( x \sin x \), we will use the method of integration by parts. The formula for integration by parts is given by: \[ \int u \, dv = uv - \int v \, du \] ### Step 1: Choose \( u \) and \( dv \) We choose: - \( u = x \) (which we will differentiate) - \( dv = \sin x \, dx \) (which we will integrate) ### Step 2: Differentiate \( u \) and Integrate \( dv \) Now we differentiate \( u \) and integrate \( dv \): - \( du = dx \) - \( v = \int \sin x \, dx = -\cos x \) ### Step 3: Apply the Integration by Parts Formula Now we apply the integration by parts formula: \[ \int x \sin x \, dx = uv - \int v \, du \] Substituting the values we found: \[ = x(-\cos x) - \int (-\cos x) \, dx \] This simplifies to: \[ = -x \cos x + \int \cos x \, dx \] ### Step 4: Integrate \( \cos x \) Now we integrate \( \cos x \): \[ \int \cos x \, dx = \sin x \] ### Step 5: Combine the Results Putting it all together, we have: \[ \int x \sin x \, dx = -x \cos x + \sin x + C \] where \( C \) is the constant of integration. ### Final Answer Thus, the integral of \( x \sin x \) is: \[ \int x \sin x \, dx = -x \cos x + \sin x + C \]
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