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Which of the following is wrong?...

Which of the following is wrong?

A

`int sqrt(x^2-a^2)dx=x/2sqrt(x^2-a^2)+a^2/2 log|x+sqrt(x^2+a^2)|+c`

B

`int sqrt(x^2+a^2)dx=x/2sqrt(x^2+a^2)+a^2/2 log|x+sqrt(x^2+a^2)|+c`

C

`int 1/sqrt(x^2+a^2) dx=log|x+sqrt(x^2+a^2)|+c`

D

`int 1/sqrt(x^2-a^2) dx=log|x+sqrt(x^2-a^2)|+c`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given options is wrong, we will analyze the integration formulas mentioned in the transcript step by step. ### Step-by-Step Solution: 1. **Identify the Formulas**: We have several integration formulas to consider. The relevant ones from the transcript are: - \( \int \sqrt{x^2 - a^2} \, dx = \frac{1}{2} x \sqrt{x^2 - a^2} - \frac{a^2}{2} \log(x + \sqrt{x^2 - a^2}) + C \) - \( \int \sqrt{x^2 + a^2} \, dx = \frac{1}{2} x \sqrt{x^2 + a^2} + \frac{a^2}{2} \log(x + \sqrt{x^2 + a^2}) + C \) - \( \int \frac{1}{\sqrt{x^2 + a^2}} \, dx = \log(x + \sqrt{x^2 + a^2}) + C \) - \( \int \frac{1}{\sqrt{x^2 - a^2}} \, dx = \log(x + \sqrt{x^2 - a^2}) + C \) - \( \int \frac{1}{a \sqrt{a^2 - x^2}} \, dx = \sin^{-1}\left(\frac{x}{a}\right) + C \) - \( \int \sqrt{a^2 - x^2} \, dx = \frac{1}{2} x \sqrt{a^2 - x^2} + \frac{a^2}{2} \sin^{-1}\left(\frac{x}{a}\right) + C \) 2. **Evaluate Each Option**: - **Option 1**: \( \int (x^2 - a^2) \, dx = \frac{x^3}{3} - a^2 x + C \) - This is the correct integral for \( x^2 - a^2 \). - **Option 2**: \( \int (x^2 + a^2) \, dx = \frac{x^3}{3} + a^2 x + C \) - This is also correct. - **Option 3**: \( \int \frac{1}{\sqrt{x^2 + a^2}} \, dx = \log(x + \sqrt{x^2 + a^2}) + C \) - This is correct as per the formula. - **Option 4**: \( \int \frac{1}{\sqrt{x^2 - a^2}} \, dx = \log(x + \sqrt{x^2 - a^2}) + C \) - This is also correct according to the formula. 3. **Identify the Wrong Option**: - The first option is the only one that does not match the expected integration result, as it incorrectly states the integral of \( x^2 - a^2 \). ### Conclusion: The wrong option is **Option 1**.
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