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Find the area of the circle 4x^2+4y^2=9...

Find the area of the circle `4x^2+4y^2=9`which is interior to the parabola `x^2=4y`.

Text Solution

Verified by Experts

The correct Answer is:
`((2 sqrt2)/(6) + (9)/(4) sin ^(-1) "" (2 sqrt2)/(3))` sq. units.
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Find the area of circle 4x^(2)+4y^(2)=9 which is interior to the parabola x^(2)=4y

Find the area of the circle 4x^2+4y^2=9 which is interior to parabola y^2=4x .

Knowledge Check

  • If the circle x^(2)+y^(2)+2ax=0, a in R touches the parabola y^(2)=4x , them

    A
    `a in (-oo, 0)`
    B
    `a in (0, oo)`
    C
    `a in (2, oo)`
    D
    none of these

  • The equations of the tangents of the circle x^2+y^2=9 which are parallel to line 3x+4y=0 are

    A
    3x+4y+15=0
    B
    4x-3y+15=0
    C
    4x+3y+15=0
    D
    3x+4y+45=0

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    Find the equation of the circle which is concentric with the circle x^2 +y^2 - 4x+6y-3=0 and the double of its area.

    Find the equation of line which is normal to the parabola x^(2)=4y and touches the parabola y^(2)=12x .

    Find the area of the region which is inside the parabola y = - x^(2) + 6x - 5 , out the side the parabola y = - x^(2) + 4x - 3 and left of the stragiht line y = 3x-15 .

    Find area of the ellipse 4x ^(2) + 9y ^(2) = 36.

    Find the area of the figure contained between the parabola x^(2)= 4y and the witch of Agnesi y= (8)/(x^(2)+4)

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