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Find the area of the circle 4x^2+4y^2=9...

Find the area of the circle `4x^2+4y^2=9`which is interior to the parabola `x^2=4y`.

Text Solution

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The correct Answer is:
`((2 sqrt2)/(6) + (9)/(4) sin ^(-1) "" (2 sqrt2)/(3))` sq. units.
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